सोमवार, जून 11, 2018

BODMAS rule se bracket waale questions solve karna sikhiye

Hello friends !! Aaj hum aapko BODMAS rule se bracket waale questions ko solve karna sikhayenge. BODMAS rule kya hai ? aur BODMAS rule ka use karke simple questions ko kaise solve karte hai ? Ye sab hum aapko part-1 aur part-2 me sikha chuke hai. Agar aapne abhi tak read nahi kiya to humne iss article ke last me dono part ka link diya hai . Aap waha se read kar sakte hai.
Aaj hum aapke request par BODMAS rule part-3 lekar aaye hai. Iss part me hum aapko BODMAS rule ke use se kuch tough questions meas "kathin questions" ko solve karna sikhayenge. Abhi tak humne aapko kewal simple question ko solve karna sikhaya hai. Aapne part-2 me question ko dekha hoga to ye dhyaan diya hoga ki, wo sabhi questions me bracket ka use nahi tha. Means part-2 me sabhi questions without bracket waale the. Aaj hum aapko bracket waale question ko BODMAS rule ka use karke solve karna sikhayenge. Chaliye start karte hai.


BODMAS rule for Bracket questions and solution


BODMAS rule se Bracket waale questions ko solve karna sikhiye

Bracket waale questions ko solve karne se pahle hume Bracket ke baare me kuch jaan lete hai.
 Bracket -:  Bracket ko hindi me kosthak (कोष्ठक) kahte hai. Kosthk ka use karke hum question ko sahi takrke se solve karte hai. Iss ko acche se samjne ke liye nichye diya huaa sentence ko pade.
Sentence-: "5 aur 4 ke yogphal me se 3 multiply kariye."
Uppar diye sentence ko hum without bracket iss prakar se likh lar solve kar sakte.
5+4×3 = 5+12 = 17 me agar hum witIsska use karke hum bade-bade questions ko solve karte hai. Mathematics me Bracket 4 types ke hote hai. Jo iss prakar se niche diya gaya hai:

S.N. Bracket sign Bracket name
1.
  Rekha kosthk (Vinculum)

2.
( )
 Chhota kosthk (Parentheses/Round bracket)
3.
{ }
 Majhla kosthk (Braces/Curly bracket)
4.
[ ]
 Big bracket (Square bracket)


 Bracket ko solve karna : 

Jab kisi question me 1 se jaada bracket ho to bracket niche bataye order se solve karte hai:
Suppose kariye ki, question me sabhi 4 bracket diye ho to:
(1)."一" viniculum (rekha kosthk)-: Agar question me rekha kosthk diya ho to iss ko sabse pahle solve karte hai.
(2). "( )" parentheses / round bracket/ small bracket (chhota kosthk)-: rekha kosthk ke baad chhota kosthk ko solve karte hai.
(3). "{ }" braces/Curly bracket (majhla kosthk)-: Curly bracket ko rekha aur chhota bracket ke baad solve karte hai.
(4). "[ ]" square bracket (bada kosthk ) -: square bracket ko sabse last me solve karte hai.

(i) Agar kisi bracket ke pahle minus "-" ho to bracket hatane par bracket ke andar ke sabhi number ka sign change ho jate hai. Ye change kuch iss prakar se hota hai:
(a) Agar bracket ke andar "+" sign waale number ho to wo "-" me change ho jaate hai.
(b) Agar bracket ke andar  "-" sign waale number ho to wo "+" me change ho jaate hai.
Example: 6-(5-3) iss me chhota bracket "( )" se pahle "-" minus laga hai isliye jab hum bracket ko hatayenge tab bracket ke andar ke number +5 se -5 me aur -3 se 3 me change ho jaayega.
Jaise-: 6-(5-3) = 6-5+3 
(ii) Agar kisi bracket ke pahle "+" (plus) ho to bracket ko hatane par bracket ke andar ke sabhi number ke sign change nahi hote hai.
Example-: 5+{4-3} = 5+4-3

(iii) Agar kisi bracket ke pahle yaa bracket ke baad me koi number diya ho aur uss number aur bracket ke beech me koi sign nahi diya ho to waha par hum multiply "×" ka sign maante hai.
Example-: 4(6-3) = 4×(6-3)

(iv) Kisi bhi bracket ko hatane se pahle uss bracket ke andar likhe numbers ko solve kar lena chaahiye.
Example-: 4-5+(8×4-30) 
                 = 4-5+(32-30)
                 = 4-5+2

Bracket waale 10 questions with full solutions

Ab 10 bracket waale question ko BADMAS rule se solve karna sikhate hai. Hum niche 10 questions ko solve karenge. Aap unn question ko step-by-step samjhe aur khud se bhi practice kare.
                          
#Q-1. 14÷10-3
Solution-:             
            ⇒14÷10-3
            = 14÷7         【solve "line bracket"】
            = 2 Ans.

#Q-2. 5+(6-4)
Solution-:
⇒ 5+(6-4)
= 5+2                   【solve "small bracket"】
= 7 Ans.

#Q-3.  (-7)+{12÷(6-3)}
Solution-: 
⇒(-7)+{12÷(6-3)}【solve "small bracket"】
= (-7)+{12÷3}      【solve "curly bracket"】
= (-7)+4
= -3  Ans.
                                
#Q-4. 6-8(12-7+2)
Solution-: 
                             
⇒ 6-8×(12-7+2)
= 6-8×(12-9)        【solve "line bracket"】
= 6-8×3                【solve "small bracket"】
= 6-24
= -18   Ans.



#Q-5.  12-[2+{13-(14-6)}]
Solution-:
 12-[2+{13-(14-6)}]
= 12-[2+{13-8}   【solve "small bracket"】
= 12-[2+5]          【solve "Curly bracket"】
= 12-7                 【solve "square bracket"】
= 5 Ans.
                                       
#Q-6. (7-2)×[5-{6+8-3}]
Solution-:            
⇒(7-2)×[5-{6+8-3}]
= (7-2)×[5-{6+5}]    【solve "line bracket"】
= 5×[5-{6+5}]        【solve "small bracket】
= 5×[5-11]              【solve "curly bracket"】
=5×(-6)              【solve "square bracket"】
= -30   Ans.

#Q-7. (-2)+(-12)÷4-[(-3)×(-4)-{3-(1-2}]
Solution-:
⇒(-2)+(-12)÷4-[(-3)×(-4)-{3-(1-2)}]
= (-2)+(-3)-[12-{3-(-1)}]
                            【solve "small bracket"】
= (-5)-[12-{3+1}]
                            【solve "small bracket"】
= (-5)-[12-4] 【solve "curly bracket"】
= (-5)-8
= -13 Ans.
                   
#Q-8. (-3){(-8)+(-64)}÷(-4)-(2-4)(-3)
Solution-:
⇒(-3){(-8)+(-64)}÷(-4)-(2-4)(-3)
= (-3){(-8)+(-64)}÷(-4)-(-2)×(-3)
                            【solve "small bracket"】
=(-3){(-8)+(-64)}÷(-4)-6
                            【solve "multiplication"】
=(-3){-8-64}÷(-4)-6
                             【solve "small bracket"】
=(-3)×(-72)÷(-4)-6 【solve "curly bracket"】
=(-3)×(-18)-6
=54-6
=48 Ans.
                                     
#Q-9.  4-[4-{4-(4-4-4)}]
Solution-:         
⇒4-[4-{4-(4-4-4)}]
= 4-[4-{4-(4-0)}]      【solve "line bracket"】= 4-[4-{4-4}]          【solve "small bracket"】
= 4-[4-0]            【solve "square bracket"】
= 4-4
= 0 Ans.
                                    
#Q-10. 12-(-2)(3-2-1)÷2{2+(-2)×(-3)}
Solution-:  
                           
⇒12-(-2)(3-2-1)÷2{2+(-2)×(-3)}
= 12-(-2)(3-1)÷2{2+(-2)×(-3)}
                             【solve "line bracket"】
= 12+2×2÷2{2+6}
                             【solve "small bracket"】
= 12+2×2÷2×8     【solve "curly bracket"】
= 12+2×1×8                   【solve "division"】
= 12+16                【solve "multiplication"】
= 28  Ans.

Aaj ke iss BODMAS rule part-3 me kewal itana hi friends. I hope ki , aapko aaj ka ye part achhe se samjh aaya hoga.
Agar aapko koi problem ya doubt ho to comment karke jarur puche. Hum aapke problem ya doubt ko solve karne ki puri koshish karenge.
Agar aapko ye topic achhe se samjh aaya to please ek share jarur kare.




Hum aapko batade ki humne apne last article Happy Birthday Maths Tricks in Hindi me plan-1 me bataya tha ki, Sunday ko 8am - 9am (on india time) par hum Live Chat start karenge. To humne last Sunday Jun 03 aur June 10 se ye plan start kar diya hai. Next Live Chat Sunday June 17 ko bataye huye time par hoga. Aap ussi time par humse Live chat kar sakte hai.

• BODMAS rule part-1
• BODMAS rule ka use kark 10 question solve karna sikhiye.

46 टिप्‍पणियां:

  1. Sir Bahot Help hua meko .You tube pr ek v video smjh mein ni aya but apneven bahot Achhe se explain Kiya Thanqq Sir

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  2. Hlo sir plz app j batao k jese appne bodmas ka method batea woh tu braket me use nhi ho raha kese pta chlega k bracket me jo dea hai use add krna hai ja sub krna hai plz advise de

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  3. उत्तर
    1. 1-{1÷[1+3÷(4+1÷(2+(1÷7)))]}
      = 1-{1÷[1+3÷(4+1÷(2+1/7))]}
      ={1÷[1+3÷(4+1÷15/7)]}
      ={1÷[1+3÷(4+7/15)]}
      ={1÷[1+3÷67/15]}
      ={1÷[1+45/67]}
      ={1÷112/67}
      =67/112 Ans.

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  4. उत्तर
    1. Tachnical raj Sorry humse galti ho gayi. Batane ke liye thanks:)
      1-{1÷[1+3÷(4+1÷(2+(1÷7)))]}
      = 1-{1÷[1+3÷(4+1÷(2+1/7))]}
      =1-{1÷[1+3÷(4+1÷15/7)]}
      =1-{1÷[1+3÷(4+7/15)]}
      =1-{1÷[1+3÷67/15]}
      =1-{1÷[1+45/67]}
      =1-{1÷112/67}
      =1-67/112
      =(112-67)/67
      = 45/67 Ans.

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    2. sir plz btaiye ismey 15 kha se aa rha hai....(2+1/7))]} ise solve karne pr?

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    3. SIR MUJHE SAMJHNE M PROBLEM AA RHI HAI MERA MATH WEEK HAI PLZ HELP KRIYE..SIR YEH ISMEY ISE(2+1/7))]} SOLVE KRNE PR YEH 15/7)]} KAISE AAYA ?

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    4. Ashish ji aapke question ko humne detail solve kiya hai. Aap "YAHA CLICK" karke question no. 334 dekiye. Aapko jarur samjh aayega. Agar nahi aaya to phir se puchh sakte hai.

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    5. Sir yaha pr questions ka answer 45/112 hona chahiye to apka answers 45/67 kaise aa gya.. plz detail me samjhaiye isko ki 45/67 kaise aaya

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    6. Sorry ye humari galati hai. Yaha par Answer 45/112 hi aayega.

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  5. In solution of question 8 at last you wrote 54-6=58 how is it possible... 54-6=48 not 58

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  6. In solution of question number 8 you wrote 54-6=58 how is it possible. 54-6=48 not 58 .waht a silly mistake

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  7. उत्तर
    1. 24-[25-{26-(27– (vinculam over 28-29)}]
      =24-[25-{26-(27+1)}]
      =24-[25-{26-28}]
      =24-[25-(-2)]
      =24-[25+2]
      =24-27
      =-3 Answer.

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  8. उत्तर
    1. 25-5[2+3{2-2(5-3)+5}-10]÷4
      =25-5[2+3{2-2×2+5}-10]÷4
      =25-5[2+3{2-4+5}-10]÷4
      =25-5[2+3×3-10]÷4
      =25-5[2+9-10]÷4
      =25-5×1÷4
      =25-5×1/4
      =25-5/4
      =(100-5)/4
      =95/4
      = 23 3/4 Ans.

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  9. 0.98002(1-0.0012/8.0000)/(0.99799-0.0012)*(1-0.000099)*(20.7-20) plz solve this plzzzz

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    उत्तर
    1. Aapka question achhe se samjh nahi aa raha hai please iss question ka image humre Facebook page par send kare.

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  10. 31/10×3/10+7/5÷20=?
    Sir mujhe is question ka solution mil sakta h

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  11. 6-8×(12-7+2)
    = 6-8×(12-9) 【solve "line bracket"】
    = 6-8×3 【solve "small bracket"】
    = 6-24
    = -18 Ans is this correct?

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  12. उत्तर
    1. MR.AEZ ji, 6÷2(2+1) iss question ko hum iss prakar se solve kar sakte hai-:
      6÷2(2+1)
      = 6÷2×3
      = 3×3
      = 9 Ans.

      हटाएं
  13. उत्तर
    1. 19+8÷ {(51-3)-5×3}

      Solution-: BODMAS rule ke according Sabse pahle "small bracket", uske baad "curly bracket"ko solve karenge.
      →19+8÷{(51-3)-5×3}
      →19+8÷{48-5×3}
      →19+8÷{48-15}
      →19+8÷33
      →19+8/33
      →(33×19+8)/33
      →(627+8)/33
      →635/33
      → 19 8/33 Ans.

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