शनिवार, मार्च 10, 2018

Question Answer Aapke send kiye gaye question ka answer yaha hai part-2

Aapke send kiye gaye question ka answer yaha hai part-2

by maths tricks on मार्च 10, 2018 in Question Answer

Last update-: Dec 21, 2018

Aapke send kiye gaye question ka answer yaha hai part-2

Aapke send kiye gaye question ka answer yaha hai part-1
Iss page par Mar 09,2018 - Dec 17, 2018 tak ke Question hai. Agar aapne iss Date ke baad question send kiya hai. Dec 18, 2018 ke liye next part Aapke send kiye gaye question ka answer yaha hai part-3 padhiye.

Sender name -: Jaya gahlot
Date-: Mar 09, 2018

Kaise send kiya -: contact form

#Q-251 Sir muje set ke thoerm ke question kese vo solve krne btao

Answer-: Jaya ji, hum jarur batayenge . Aap class aur question send kariye.

Sender name -: brajesh vaishnew
Date-: Mar 10, 2018

Kaise send kiya -: contact form

#Q-252. q/no.3 k ansare360

Answer-: brajesh ji , aap kon se question ki baat kar rahe hai.

Sender name -: ankit Mishra
Date-: Mar 11, 2018

Kaise send kiya -: contact form

#Q-253. X+y/5 ka man bataye Agar x:y=2:3

Solution-: Suppose karte hai ki, x = 2k and y = 3k

x+y/5 = 2k + 3k/5

= (10k+3k)/5

= 13k/5 Ans.

Sender name -: umesh yadav
Date-: Mar 14, 2018

Kaise send kiya -: contact form

#Q254. X ka 1\5 nikala fir ses ka 1\10 nikala to kitna bachega

Solution-: Pahle X ka 1/5 = X/5 aur X ka 1/10 = X/10.

Ab pahle X me se 1/5 nikala means X-X/5 = 4X/5 ses bachega

Ab 4X/5 me se 1/10 nikala means

4X/5 - X/10 = (8X-X)/10

= 7X/10 bachega Answer.

Sender name -: Aadarsh Patel
Date-: Mar 18, 2018

Kaise send kiya -: Facebook page par massage

#Q-255. 5000 rs ka 5% k hisab se 1 saal k kitna interest in rs hua h

Solution-: Principal amount (P) = 5000, rate (R) = 5% and time (T) = 1 year.

Formula -: interest = (P×R×T)/100

Interest = (5000×5×1)/100

= 250

Isliye 1 saal me interest = 250 rs hoga Answer.

Also learn-: Simple interest ke 10+ word problem question with solution

Sender name -: Saroj verma
Date-: Mar 19, 2018

Kaise send kiya -: contact form

#Q256. m-6=6 ko hal karo

Solution-: m-6=6 ⇒m=6+6 = 12 Answer.

Sender name -: अनुज
Date-: Mar 22, 2018

Kaise send kiya -: contact form

#Q257. 64 कितने परसेंट कम है 68 से

Solution-: original no. (x) = 68 and new no. (y) = 64.

Formula-:

% less = (x-y) ×100

= 68-64 ×100

= (4/68)×100

= (1/17)×100

= 5.88

Isliye 64 , 68 se 5.88% kam hai.

Sender name -: Shreya Raj
Date-: Mar 25, 2018

Kaise send kiya -: contact form

#Q-258. A,B se 40% jyda h or B,C se 20% km h to A:C kya hoga?

Solution-: question me diya hai ki , A,B se 40% jyda hai isliye-:

A = B+B ka 40%

= (140/100)×B

Or A/B = 14/10

question me phir diya hai ki, B,C se 20% kam hai isliye -:

B = C - C ka 20%

= (80/100)×C

Or B/C = 8/10

Ab hume A:C maalum karna hai isliye -:

A = A × B

C B C

= 14 × 8

10 10

= 28/25

Isliye A:C = 28:25 Answer.

Sender name -: Vishal Sharma
Date-: Mar 28, 2018

Kaise send kiya -: contact form

#Q-259. Sambahu tribhuj ki prtyek bhuja ki lambai L Ho, to sidh kijie ki, Sambahu tribhuj ka khsetrfal(area) root3/4(l)squre h

Answer-: Vishal ji , hum jald hi iss topic par ek complete article publish karke aapke problem ko solve karenge. Please aap humse add rahe.

Sender name -: hariom rajput
Date-: Apr 04, 2018

Kaise send kiya -: contact form

#Q-260. 7 लोगो में 28 रुपये बराबर बाटने है तो प्रत्येक को 13 रूपये आने चाहिए ans fast

Solution-: hariom ji , I think ye possible nahi hai.

Sender name -: Himanshu shukla
Date-: Apr 04, 2018

Kaise send kiya -: contact form

#Q-261. Nameste Sir, Kisi sankhya Ka bhag ugly sankhya ke bhag se 3 adhik hai vah sankhya gyat kijiye

Solution-: Himanshu ji, hume aapke question me kuch mistake lag raha hai ya ho sakta hai ki mistake ho. Hume niche diye points par mistake lag raha hai:

(1). " kisi sankhya ka bhag ugly sankhya ke bhag se 3 adhik hai "

Kitana bhag ugly sankhya ke kitne bhag se 3 adhik hai.

Sender name -: Razi Roman
Date-: Apr 08, 2018

Kaise send kiya -: Facebook page par massage

#Q-262. 16 insaan 10din me dhaan kat sakta hai to 8din me katne k liye kina insaan chahiye

Solution-: Diya hai M₁ = 16, D₁ = 10 and D₂ = 8

Suppose karte hai ki, 8 din me katne ke liye M₂ insaan chahiye.

Isliye formula: M₁×D₁ = M₂×D₂ ka use karne par.

16×10 = M₂×8

M₂ = 160/8 = 20

Isliye 8 din me dhaan katne ke liye 20 insaan chahiye. Answer.

Sender name -: Jamshaid Azad
Date-: Apr 12, 2018

Kaise send kiya -: contact form

#Q-263 4 4 4 4=20 kaise hoga

Solution-: Iss question ko solve karne ke liye hum 3 operation lenge ÷,+ aur ×.

Sabse pahle 4÷4 = 1 ab 1 me next 4 add karenge 1+4 = 5 phir 5 ka multiply next 4 se karenge 5×4 = 20

Sender name -: Ashish yadav
Date-: Apr 13, 2018

Kaise send kiya -: contact form

#Q-264. Send other theory of class of 10

Answer-: Ashish yadav ji hum jarur class 10 ke other theory ko share karenge.

Sender name -: Bhupendra kumar
Date-: Apr 20, 2018

Kaise send kiya -: contact form

#Q-265. 2 2 5 9 10 Iska answer or formula bta do sir

Answer-: Bhupendra ji , hume aapka question complete nahi lag raha hai. Please apna question complete send kariye.

Sender name -: devendra
Date-: Apr 25, 2018

Kaise send kiya -: contact form

#Q-266. dear sir, namaste. mai devendra baat kar raha hu. mai to maths subject ka fan hu. ap ke is blog par maths ke jo bhi post hai vo email ke madhyam se mai prapt karna chata hu. thanks devendra

Answer-: Namaste devendra ji, agar aap humare post ko email par prapt karna chahate hai to iske liye aapko Email subscription karna hoga . Agar aap karna chahte hai to nichey diye only 2 steps ko follow kariye:

Step-1. Humne niche ek Follow by email ka box diya hai aap scroll karke dekh sakte hai.

Follow by email ka Image iss type ka hai:

Iss box me aapko apna pura email address daalkar SUBMIT bhtton ko dabana hai.

Step-2. Jaise hi aap step-1 complete kar lenge. Uske baad aapke ussi email par FeedBurner Email Subscription se ek mail aayega. Iss mail ko open karke usme diye huye link par click karke active karna hai. Activate karte hi ek new window me likha rahega Email Subscription confirmed

Bas aapne successfully email subscription kar liya. Ab aap humare sabhi new post ko email par prapt kar sakte hai.

Agar aapko koi problem ho rahi ho to aap jarur puche. Hum aapke problem ko solve karne ki puri koshish karenge.

Sender name -: Ravendra kar
Date-: Apr 26, 2018

Kaise send kiya -: Facebook page massage

#Q-267. 23,25,27,....71 ka yogphal gyat kijiye.

Solution-: T₁ = 23, T₂ = 25 aur T₃ = 27 hum dekh sakte hai ki, T₂-T₁ = T₃-T₂ , isliye diye huye sabhi number samantar shredi (Arithmetic progression ) me hai .

Isliye diye huye sabhi numbers ka yogphal = samantar shredi ka yogphal.

Samantar shredi ke "n" numbers ka yogphal =

S = n/2×(a+l)

Yaha par n = pado ki sankhya, a = samantar shredi ka first number, aur l = last number.

To hum question me dekh sakte hai ki, a = 23 , l = 71 , d = T₂-T₁ = 25-23 = 2 aur n =??

Means hum n = total kitene numbers(pad) hai malum karna hoga.

Suppose karte hai ki, diye huye samantar shredi me total n numbers hai . Aur hum dekh sakte hai ki , n waa numbers = 71

Lekin hum ek formula se jaante hai ki,

n waa numbers = a+(n-1)×d

71 = 23+(n-1)×2

⇒ 71 = 23+2n-2

⇒ 71 = 23-2+2n

⇒ 71 = 21+2n

⇒ 71-21 = 2n

⇒ 50 = 2n

⇒ n = 25

Bas ab sabhi value Samantar shredi ke "n" numbers ka yogphal =

S = n/2×(a+l) me rakh kar solve karna hai.

S = 25/2(23+71)

S = 25/2×(94)

S = 25×47

S = 1175

Isliye diye huye sabhi numbers ka yogphal 1175 hoga. Answer

Sender name -: Ravendra kar
Date-: Apr 27, 2018

Kaise send kiya -: Facebook page massage

#Q-268. एक कक्षा में लड़कियो की संख्या , लड़को की संख्या से दोगुनी है । निम्न में से कौन सी संख्या कक्षा में कुल विद्यार्थी की संख्या को निरूपित नहीं करता है :

(i)35 (ii)24 (iii)42 (iv)36 (v)54

Solution-: Suppose karte hai ki, ladako ki sankhya = x

Tab ladakIyo ki sankhya = 2x

Isliye total vidhyarthi ki sankhya = x+2x = 3x

Ab hum ek-ek karke options (i) 35, (ii) 24, (iii) 42, (iv) 36 aur (v) 54 ko check karenge.

Suppose karte hai ki 35 total vidhyarthi ki sankhya ko nirupit karta hai to

3x = 35

x = 35/3 = 11.67

Aap dekh sakte hai ki x ki value decimal me aa raha hai joki impossible hai kyuki x ladako ki sankhya hai aur ladako ki sankhya kabhi bhi decimal me nahi aa sakti.

Isliye humne jo suppose kiya hai ki 35 total vidhyarthi ki sankhya hai ye wrong hai.

Means, 35 vidhyarthi ki sankhya ko nirupit nahi karta hai.

Aap baaki sabhi options ko jab check karenge to x ki value decimal me nahi aayegi.

Sender name -: Ravendra kar
Date-: Apr 28, 2018

Kaise send kiya -: Facebook page massage

#Q-269. एक नदी धारा का वेग 4km/h है । एक नाव एक निश्चित बिन्दु से चल कर 6 km की दुरी तय करने के बाद वापस प्रारम्भिक बिंदु पर 2 घण्टे में पहुँचती है । शान्त जल में नाव की चाल क्या होगी ?

Solution-: Suppose karte hai ki shant jal me naav ki chaal = x

Dhaara ki disha me jaane par naav ka chaal = x+4 , tab Dhaara ki disha me total time = kul duri/kul time

time = 6/(x+4)

Issi prakar se dhaara ke opposite naav ki chaal = x-4 , tab dhaara ke opposite total time = 6/(x-4)

Ab total jaane aur aane me total laga time

6 + 6

(x+4) (x-4)

But question me diye hai ki jaane aur aane me laga total time = 2 hours.

Isliye 6 + 6 = 2

(x+4) (x-4)

⇒ 1 + 1 = 1

(x+4) (x-4) 3

⇒ x-4+x+4 = 1

(x+4)(x-4) 3

⇒ 2x = 1

x² - 16 3

⇒ x² - 16 = 6x

⇒ x² - 6x - 16 = 0

⇒ (x-8)(x+2) = 0

⇒ x = 8 km/h Answer.

Sender name -: Shashibhushan tiwari
Date-: Apr 28, 2018

Kaise send kiya -: contact form

#Q-270. 148000 ko teen part me divide kr firsht part 4% rate PR 5 year k lie Second part 5% rate PR 10 year k lie And third part 10% rate PR 8 year k lie dia gaya to if teeno conditions me amount same ho to every principal kya hoga

Is questions ko kese solve karen

Solution-: Suppose karte hai ki, 148000 ko teen part me iss prakar divide kiya gaya:

1st part = x, 2nd part = y and 3rd part = z

x+y+z = 148000 ......(i)

Ab according to question 1st part ka interest = x×4×5

100

= x/5

Issi prakar se 2nd part ka interest = y×5×10

100

= y/2

Aur 3rd part ka interest = z× 10×8

100

= 4z/5

Ab phir se according to question, ye teeno part ka amount equal hai. Means, x = y = 4z

5 2 5

Ab 1st and 2nd part se,

x = y

5 2

y = 2x/5

Ab 1st and 3rd part se,

x = 4z
5 5

z = x/4
Ab eq(i) me y and z value rakhne par:
x+y+z = 148000
x+(2x/5)+(x/4) = 148000
33x/20 = 148000
x = (148000×20)÷33
x = 89696.96
Ab x ki value se y and z ki value calculate karenge.
y = 2x/5 = (2×89696.96)/5
= 35878.78

z = x/4 = 89696.96/4
= 22424.24

To iss prakar se x,y aur z principal amount honge.

Sender name -: Raunak singh
Date-: Apr 30, 2018

Kaise send kiya -: contact form

#Q-271. hello I am raunak can you help me

Answer-: Hello raunak, Yes I can help you. Boliye hum aapki kya help kar sakte hai ?

Sender name -: Niraj kumar
Date-: May 09, 2018

Kaise send kiya -: Facebook page par massage

#Q-272. sir agar koi vastu ki keemat 180 rs me 1kg hai to mere paas 250 rs hai usme mujhe kitna milega

Solution-: 180 rs me 1 kg mil raha hai. Means, 180 rs = 1 kg

⇒ 1 rs = 1/180 kg

Isliye 250 rs = 250/180 kg

= 1.38 kg

Means , aapko 250 rs me 1.38 kg milega. Answer.

Sender name -: vinod kushwaha
Date-: May 11, 2018

Kaise send kiya -: contact form

#Q-273. please sir. 23 years ko decimals no main kaise likhege

Solution-: Vinod ji, aapka question complete nahi hai . Please complete question send kariye.

Sender name -: Shubham kumawat
Date-: May 13, 2018

Kaise send kiya -: contact form

#Q-274. 1 se 9 take ki sankya ko aese likho ki koi bhi sankya double na ho

Solution-: Shubham ji, 1 se 9 tak ko hum normal likh sakte hai . 123456789 koi bhi sankya double nahi hai.

Sender name -: Whatsapp all video
Date-: May 15, 2018

Kaise send kiya -: comment

#Q-275. एक परीक्षा में किसी संख्या के 4/5 गुने तथा उसके 2/3 गुने को जोड़ना था लेकिन छात्र ने गलती से उस संख्या के 5/4 गुने तथा उसके 3/2 गुने को जोड़ दिया परिकलन में त्रुटि प्रतिशत कितना है ?

Solution-: Suppose karte hai ki, koi sankhya = x , ab iss ka 4/5 guna aur 2x/3 guna plus karna hai.

Means, 4x/5 + 2x/3 = 22x/15 (correct answer)

But mistake ke kaaran student ne

5x/4 + 3x/2 = 11x/4 (wrong answer) kar diya.

Isliye , percentage error =

correct - wrong ×100

correct

= (22x/15) - (11x/4) ×100

22x/15

= -77x/60 ×100

22x/15

= (- 7/8)×100 = -87.5%

= 87.5% (minus sign remove) Answer.

Sender name -: Rajkumar k
Date-: May 16, 2018

Kaise send kiya -: contact form

#Q-276. 1 kilo chini ka dam 27 rupya to 20 gram chini ka dam kitna hoga

Solution-: Diya hai : 1 kg = 27 rs aur hum jaante hai ki ,1 kg = 1000 gram

Means, 1000 gram = 27 rs

⇒ 1 gram = 27/1000 rs

Ab hume 20 gram ka dam batana hai isliye dono side 20 se multiply karenge.

⇒ 20 gram = (20)×(27/1000) rs

= 0.54 rs

20 gram chini ka dam = 0.54 rs hoga.

Sender name -: Chandan Kumar
Date-: May 16, 2018

Kaise send kiya -: contact form

#Q-277. 10^5/135×10^6×3.57×10^-2

Solution-: 10⁵/135×10⁶×3.57×10^-²

= 10⁵/135×3.57×10⁶^-²

= 10⁵/135×3.57×10⁴

= 10/135×3.57 [ 10⁵ aur 10⁴ cancel]

= 10/481.95

= 0.0207 (approx.) Answer.

Sender name -: Sagar singh
Date-: May 18, 2018

Kaise send kiya -: contact form

#Q-278. 1 se 1000 tak ke bich kitni primey sankhya hoti h

Solution-: 1 se 1000 ke bich infinite (ananant) primey sankhya hoti hai.

Sender name -: Prabhakar Verma
Date-: May 20, 2018

Kaise send kiya -: Facebook page par massage

#Q-279. Sir kisi saman ka kimat 30% add kar 325/- hai to uska purchasing rate kaise nikal sakte hai. Please define

Solution-: Suppose kar lete hai ki, uska purchasing rate = x

Ab x ka 30% add karne par 325 ho jaata hai. Means, pahle hum x ka 30% nikalenge.

x ka 30% = 30x/100 = 3x/10

Ab hum 3x/10 ko x me add karenge aur 325 ke equal rakhenge.

x+(3x/10) = 325

⇒ (10x+3x)/10 = 325

⇒ 13x/10 = 325

⇒ 13x = 325×10

⇒ x = 3250/13

⇒ x = 250

Means, purchasing rate =₹250 hai. Answer.

Sender name -: Komal
Date-: May 28, 2018

Kaise send kiya -: Contact form

#Q-280. 1 gadriye k pas 17 sheep h . sabhi lekin 9 mar gai. To batao ki zinda kitni h ?

Solution-: Gadriye ke pas 17 hai .lekin 9 mar gayi to kul jinda bachi = 17-9 = 8 Answer.

Sender name -: Giriraj sikhwal
Date-: May 28, 2018

Kaise send kiya -: Contact form

#Q-281. 2,3,4,5,7&8 se 3 word ke kitne no. Bnaye ja skte jisme 2 se devide ho

Solution-: hum jaante hai ki , jis no. ke ones place (ikaai) par 0,2,4,6,8 ho to wahi no. 2 se divide hota hai.

Diye huye number me 2,4 aur 8 hai . Jab ones place par 2 hoga -:

Jab once place par 2 hoga tab 3 anko ki sankhya banane ke liye humare paas 2 place bache hai. Ek hundred place aur ek tens place.

2 place par hume 5 anko (3,4,5,7,8) ko rakhna hai .

Hum jaante hai ki n numbers me se r numbers lekar total bane numbers = ⁿCᵣ = n!

r!(n-r)!

2 place par 5 anko (3,4,5,7,8) ko rakhne ke tarike =

⁻⁵C₂= 5!

2!(5-2)!

= 5!

2!×3!

= 5×4×3!

2!×3!

= 5×4× 3!

2×1×3!

= 10 ormula : nCr = n!/r!(n-r)!

Issi prakar se jab ones place par 4 hoga :

jab once place par 4 hoga tab phir se 2 place par 5 anko (3,4,5,7,8) ko rakhne ke tarike = ⁵C₂= 10

aur issi prakar jab ones place par 8 hoga -:

jab ones place par 8 hoga tab 2 place par 5 anko (3,4,5,7,8) ko rakhne ke tarike = ⁵C₂= 10

Total bane number jo 2 se divide honege = ⁵C₂+⁵C₂+⁵C₂

= 10+10+10

= 30 Answer.

Sender name -: Pratham Sharma
Date-: May 28, 2018

Kaise send kiya -: Contact form

#Q-282. If a=log 12base 18 , b= log 24 base 54 then the value of ab+5(a-b) is

Solution-: Diya hai: a = log₁₂18

⇒ 12ª = 18

⇒ (2×2×3)ª = 2×3×3

⇒ (2²×3)ª = 2×3²

⇒ 2²ª×3ª = 2×3²

⇒ 2²ª^-¹×3ª^-² = 1 .......(i)

Iss prakar se, b = log₂₄54

⇒ 24^b= 54

⇒ (2×2×2×3)^b= 2×3×3×3

⇒ (2³×3)^b= 2×3³

⇒ 2^3b×3^b= 2×3³

⇒ 2^3b-1×3^b-3= 1 ...........(ii)

(i) and (ii) ko equal rakhne par :

2²ª^-¹×3ª^-² = 2^3b-1×3^b-3

^{2 and 3 ke power ko compair karne par:}

2²ª^-¹ = 2^3b-1

⇒ 2a-1 = 3b-1

⇒2a-3b = 0 ......(iii)

Again, 3ª^-² = 3^b-3

⇒ a-2 = b-3

⇒ a-b+1 = 0 .........(iv)

Eq(iv) me 2 se multiply karne par :

2a-2b+2=0

2a-2b = -2 .........(v)

Eq (iii) me se (v) ko subtract karne par: -b = 2 ⇒ b = -2

Eq(iv) me b = -2 rakhne par:

a-(-2)+1 = 0

a+3 = 0

a = -3

ab+5(a-b) = (-3)×(-2)+5{(-3)-(-2)}

= 6+5{-3+2}

= 6+5{-1}

= 6-5

= 1 Answer.

Sender name -: Devendra
Date-: Jun 01, 2018

Kaise send kiya -: Contact form

#Q-283. hi Goode evening. y maths lovers. kaise hai sabh? dosto, mai khud ka short me parichay de deta hu. mera nam devendra hai.

basically mai blind"drushtihin" person hu. bachpan se muze maths subject se lagav hai. matlab bole to agar ap muze 24 hours continue muze maths karne bologe to bhiai paknevala insan nahi. kyu ki maths is my true lover. maths ki har ek chij mere nas nas me, khun ke har ek bund me baith chuki hai ki ki nind me bhi mai maths solve kar leta hu. dosto, mere role model "adarsh" r.s. ramanujan hai. unko ne apni antim saas tak maths karte rahe, halaki un ke life me bahut sari mushkile thi fir bhi unho me true lagan ke sath maths karte rahe & ek true maths genious ke rup me ham un ko jante hai.

dosto, mai yahi kehna chata hu ki, hum sabh maths genius ban sakhte hai, bas avashyakta haithode hamare soch me parivartan lane ki.

hamari soch positive rahegi to ham maths me genus kya supper fast calculater se bhi & computer laptop se bhi powerful ban jaoge. tabh bolege ki khadde me gaya calc & computer lapto. jabh mai is se supper fast hu to is ko mai kyu use karu? dosto ap sabh aise socho, ki mai maths me genius & exports ban sakta hu & ban ke hi rhunga. & us ke hisab se kadam uthao. to bhale itni bhi mushkil bhi kyu na aye to piche mat hatna. acharya chanakya ke shabd muze yad aa rahe hai. "bhag mat kar prayas, kar pryas, bhag mat"

is blog ke mukhya person se meri vinamra vinati hai, ki mai bhi apne is blog par maths ka artical bana ke upload karna chata hu to krupya muz se sampark kar ke muze margdarshan kare.

happy birthday maths tricks hindi

thank you

Answer-: Devendra ji sabse pahle to aapko thanks ki, aapne apne vichar humse share kiya. Hume motivate kiya aur hume achhi-achhi baate batayi. Aapne "R.S. Ramanujan" aur "Acharya chankya" ka jikra kiya . Bahot achha laga. Aapke word se hum aur jo issko read karega wo sabhi jarur motivate honge. Aap jaise math lovers ki hume jarurat hai. Aap jarur humare "Maths Tricks in Hindi" ke family member ban sakte ho aur apne math article ko iss blog par upload kar sakte ho. Hum jald hi isske baare me details me ek article likh kar publish karenge. Jisme full details me bataya jaayega ki kya-kya karna hai? Tab tak ke liye aap wait kare. Aapne apna intrest dikhaya iske liye aapko again Thank you !!

Sender name -: Mabendra inaniyan
Date-: Jun 02, 2018

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#Q-283. How many numbers of six digits we made by 1,2,3,4,5,6,7,8,9,0 with answer all numbers

Solution-: Diya huaa total number = 10, Ab hume inn 10 diye huye numbers se 6 digits ka number banane hai. Means hume ones, tens, hundred, thousand, ten thousand, aur lakh ki jagah par inn 10 numbers ko rakhna hai.

Lakh ke jagah par "0" nahi ho sakta kyuki tab number 6 digits ka nahi rahega.

Isliye lakh ki jagah par hum 9 numbers 1,2,3,4,5,6,7,8,9 me se kisi ek number ka rakh sakte ha.

Isliye lakh ke jagah par number ko rakhne ke total tarike = 9

Ab ten thousand ki jagah par 0 sahit sabhi 9 numbers ko rakhne ke total tarike = 10

Issi prakar se thousand, hundred, tens, ones ki jagah par hum 10,10,10,10 prakar se rakh sakte hai.

Isliye total tarike = 9×10×10×10×10×10 = 900000 Answer.

Sender name -: nibha
Date-: Jun 07, 2018

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#Q-284. 3÷4-3÷4=0 how

Solution-: nibha ji 3÷4 = 0.75 hoga.

3÷4-3÷4 = 0.75-0.75 = 0

Sender name -: Ganesh Chakor
Date-: Jun 08, 2018

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#Q-285. Sir.me 12th science ka student hu. Lekin mujhe math kuch samjme nahi ata .Mujhe examples dekha kar hi de ar lagta hai.kuch aisi strick bataye ki mujhe math se pyar hone lage.please....

Solution-: Ganesh ji, Sabse pahle to hum ye kahana chahte hai ki,math padane ke liye koi trick hai hi nahi. Issko to dhyaan se samjh kar aur read karke solve kiya jaata hai. Aur aapko math se darne ki jarurat nahi hai. Aap math se dare nahi balki issko dhyaan se samjhne ki koshish kare. Agar koi chij samjh me nahi aati to kisi apne family members ya teacher ki help le. Hum bhi aapki help kar sakte hai. Aap math me koi bhi topic pade uss topic ke basic aapko jarur maalum rahne chahiye. Tabhi aap uss topic ko samjh paayenge. Issliye Basic par jaada dhyaan dijiye. Hum ye ummid karte hai ki aapko humare answer se jarur help milegi. Koi aur problem ya doubt ho to jarur puche.

Sender name -: Vishal Delu
Date-: Jun 13, 2018

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#Q-286. 2 -2

4 7

find A inverse of each matrices

Solution-:

Hum dekh sakte hai ki, A ek 2×2 ka matrix hai.

A = [ 2 -2 ]

[ 4 7 ]

A inverse find karne ke liye hume formula ka use karna hoga.

A^-1= 1 × adjA

|A|

|A| = A ka determinant

Ab sabse pahle hum |A| calculate karte hai.

|A| = | 2 -2 |

| 1 7 |

= 2×7-(-2×1) = 14+2 = 16

Hum dekh sakte hai ki |A|≠ 0 isliye A inverse maalum kiya jaa sakta hai.

Matrix A ka adj A hum iss prakar se calculate karenge:

adjA = [C_2×2]^T

C₁₁ = 7, C₁₂ = 4, C₂₁= 2 and C₂₂ = 2

C = [ 7 4 ]

[ 2 2 ]

adjA = [ 7 2 ]

[ 4 2 ]

Isliye ab hum A^-1= ki value formula se nikalate hai.

A^-1= 1 × [ 7 2 ]

16 [ 4 2 ]

A^-1= [ 7/16 2/16 ]

[ 4/16 2/16 ]

A^-1= [ 7/16 1/8 ]

[ 4/16 1/8 ] Answer.

Sender name -: Bajrang Tanwar
Date-: Jun 13, 2018

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#Q-287. मोहन ने अपनी कुल सम्पति अपनी पत्नी , तीन पुत्रो , दो पुत्रियों तथ 5 नाती - नातिनो में इस प्रकार वितरित की कि प्रत्येक नाती-नातिन को प्रत्येक पुत्र का 1/8 भाग और प्रत्येक पुत्री का 1/10 भाग मिले . उसकी पत्नी को उसके पुत्रो एवं पुत्रियों के कुल भाग का 40% मिले. यदि प्रत्येक पुत्री को 1.25 लाख मिले हो, तो उसकी पत्नी एवं तीन नाती-नातिनो को कुल कितना धन मिला ?

(a) ₹ 32500 (b) ₹ 257500

(c) ₹ 282500 (d) निर्धारित नहीं किया जा सकता (e) इनमे से कोई नहीं

Solution-: Suppose karte hai ki, pratyek putra ko total ₹ x mila.

Means , 1 putra = ₹ x

Isliye 3 putro = ₹ 3x mile.

Question me diya hai ki, pratyek putri ko total ₹ 1.25 lakh mila.

Means , 1 putri = ₹ 125000

Isliye 3 putri = ₹ (3×125000)

= ₹ 375000 mile.

Pratyek naati - naatin ko pratyek putra ka 1/8 bhaag mila . Means Pratyek naati - naatin ko mila rupya = 3x/8 .............(i)

Phir se question me diya hai ki, Pratyek naati - naatin ko pratyek putri ka 1/10 bhaag mila . Means Pratyek naati - naatin ko mila rupya = ₹375000/10

= ₹ 37500 ..............(ii)

1 naati-naatin ko mila rupya = ₹ 37500

Isliye 3 naati-naatin ko mila rupya = 3×37500 = ₹ 112500 .........(iii)

Ab question ke according (i) aur (ii) equal honge.

Isliye 3x/8 = 37500

x = ₹100000

Isliye 3 putro = ₹ 3x

= ₹(3×100000)

= ₹ 300000 mile.

Ab question me diya hai ki, uski patni ko putro aur putriyo ke total bhaag ka 40% mila . Means , Patni ko mila = ₹(300000+375000)×40%

= ₹675000×40/100

= ₹270000

Isliye uski Patni aur 3 naati-naatin ko mila rupya

= ₹(270000+112500)

= ₹ 382500

(e) इनमे से कोई नहीं ✔️

Sender name -: shweta Rai
Date-: Jun 15, 2018

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Aapka 2 question hai:
#Q-288. sir plz explain
ek circle k ander ek square bna h...dono ka ratio kya hoga???

Solution-: shweta ji , aapka ye question complete nahi hai. Aap circle aur square ke kon si chij ka ratio jaanana chahti hai?

#Q-289. one more que sir..
9 bache kisi kaam ko 360 din m krte h. 18 aadmi 72 din m or 12 aurte 162 din m...to 4 aadmi 12 aurte or 10 bache is kaam ko kitme din m krenge?????

Solution-: • 9 bache = 360 din
Isliye, 1 bache(C) = 360×9 din ......(i)
• 18 adami = 72 din
Isliye, 1 adami(M) = 72×18 din ........(ii)
• 12 aurte = 162 din
Isliye, 1 aurte(w) = 162×12 din ........(iii)

Adami , aurte aur bache ek hi kaam ko khatan karte hai isliye,
(360×9)C = (72×18)M = (162×12)W
30C = 12M = 18W
5C = 2M = 3W

• 3 aurte= 2 adami
1 aurte = 2/3 adami
Isliye, 12 aurte = 2/3 × 12 = 8 adami
Issi prakar se • 5 children = 2 adami
Isliye, 1 children = 2/5 adami
Isliye, 10 bache = 2/5 × 10 = 4 adami
4 adami+12 aurte + 10 bache
= 4 adami + 12 aurte + 10 bache
= 16 adami

18 adami = 72 days
16 adami = (72×18)/16
= 81 days
4 adami 12 aurte 10 bache uss kaam ko 81 days me khatam karenge.

Sender name -: PANKAJ KUMAR SHARMA
Date-: Jun 15, 2018

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#Q-289. Sir mujhe bilkul bhi math nhi aati AUR ma previous me hu fir

Solution-: Pankaj hum aapki puri help karne ki koshish karenge. Aap bataye ki aapko math me kya problem hoti hai ? Hum uss ko dur karne ki koshis karenge. Aapko jarur math samjh aayega.

Sender name -: Neeraj Kalal
Date-: Jun 16, 2018

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Aapka total 5 questions hai:

#Q-290. यदि A=2,B=3,C=5,D=7 हो तो G व P का कुल मान क्या होगा

Solution-:

A = 1+1 = 2 I = 9+8 = 17

B = 2+1 = 3 J = 10+9 = 19

C = 3+2 = 5 K = 11+10 = 21

D = 4+3 = 7 L = 12+11 = 23

E = 5+4 = 9 M = 13+12 = 25

F = 6+5 =11 N = 14+13 = 27

G = 7+6 = 13 O = 15+14 = 29

H = 8+7 = 15 P = 16+15 = 31

G aur P ka kul maan = 13+31= 44 Ans.

#Q-291. अनुक्रम 3,8,13,18... का कौनसा पद 498 है?

Solution-: Question me diya hai ki, a = 3 aur d = 8-3 = 5

Suppose karte hai ki, n waa pad = 498

Isliye formula -:

n waa pad = a+(n-1)×d

498 = 3+(n-1)×5

498 = 3+5n-5

498 = -2+5n

5n = 498+2

5n = 500

n = 100

Isliye 100 waa pad 498 hoga.

#Q-292. 0.365 बार का भिन्न रूप क्या है ?

Solution-: Suppose x = 0.365365365... (i)

Dono side 1000 se multiply karne par:

1000x = 365.365365... ........(ii)

Ab (ii) me se (i) ko subtract karne par:

(1000x-x) = (365.365365...- 0.365365...)

999x = 365

x = 365/999 Ans.

#Q-293. प्रशन.वह दिघात बहुपद जिसक एक शून्यक 5+रूट 7 है वह है?

Solution-: Agar ek mul = 5+√7 hai to dusra mul = 5-√7 hoga.

Ab dwighaat bahupad ka formula use karne par :

x²-(mulo ka add)x+(mulo ka multiply) = 0

x²-(5+√7+5-√7)x+(5+√7)(5-√7) = 0

x²-10x+{5²-(√7)²} = 0

x²-10x+(25-7) = 0

x²-10x+18 = 0 Ans.

#Q-294. सोलह संख्याओ का माध्य आठ है,यदि प्रत्येक संख्या में दो जोड दिया जाए तो नया माध्य होगा?

Solution-: Suppose karte hai ki, 16 sankhya iss prakar se hai:

x₁, x₂, x₃, x₄, x₅, x₆, x₇, x₈, x₉, x₁₀, x₁₁, x₁₂, x₁₃, x₁₄, x₁₅, x₁₆,

According to the question:

(x₁+x₂+....x₁₄+x₁₅+x₁₆)/16 = 8

⇒x₁+x₂+....x₁₄+x₁₅+x₁₆ = 128 .........(i)

Ab question ke according sabhi me 2 add karne par:

⇒x₁+2+x₂+2....x₁₄+2+x₁₅+2+x₁₆+2= 128

⇒x₁+x₂+....x₁₄+x₁₅+x₁₆+32 = 128

⇒x₁+x₂+....x₁₄+x₁₅+x₁₆ = 128-32
⇒x₁+x₂+....x₁₄+x₁₅+x₁₆ = 96
⇒(x₁+x₂+....x₁₄+x₁₅+x₁₆)/16= 96/16
⇒(x₁+x₂+....x₁₄+x₁₅+x₁₆)/16 = 6

Naya maadhya = 6 Answer.

Sender name -: kashish singh
Date-: Jun 19, 2018

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#Q-295. (2/5+1/2)÷2ko simple method me solve karna hai
Solution-:

(2/5+1/2)÷2 = {(4+5)/10}÷2

= (9/10)÷2

= (9/10)×(1/2)

= (9×1)/(10×2)

= 9/20 Ans.

Sender name -: Roshan lal gurjar
Date-: Jun 19, 2018

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#Q-296. Very good

Answer-: Thanks Roshan ji.

Sender name -: Unknown
Date-: Jun 19, 2018

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#Q-297. AGR hm 10 rupey ki cheej kharidte h 1½ kilo .....to BH cheej hme kitne ruppee ki 1 kilo milegi or kitne ki ½ kilo milegi

Solution-: 1½ kilo = 1500 gram.

1500 gram = 10 rupey

1000 gram = (10×1000)/1500 rupey

= 6.67 rupey

Means 1 kilo = 6.67 rupey

½ kilo = 3.33 rupey Ans.

Sender name -: Unknown
Date-: Jun 24, 2018

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#Q-298. 24/5 * 13/3 ÷ 52/2 of 2- 5/7 of 21/25 + 3/5=?

Solution-: Iss question ko hum BODMAS rule ki help se solve karenge.
⇒ 24 × 13  ÷ 52 of 2- 5 of 21 + 3
5 3 2 7 25 5

⇒ 24 × 13  ÷ 52 ×2- 5 × 21 + 3
5 3 2 7 25 5

⇒ 24 × 13 × 2 ×2- 5 × 21 + 3
5 3 52 7 25 5

⇒ 8 × 1 × 2  ×2- 5 × 21 + 3
5 1 4 7 25 5

⇒ 8 × 1 × 1 - 5 × 21 + 3
5 1 1 7 25 5

⇒ 8 - 5 × 21 + 3
5 7 25 5

⇒ 8 - 1 × 3 + 3
5 1 5 5

⇒ 8 - 3 + 3
5 5 5

⇒ 8 Ans.
5

Sender name -: Neeraj Kalal
Date-: Jun , 2018

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#Q-299. प्रशन. समान्तर श्रेणी 3,10,17.....? का कौनसा पद इसके 13 वेपद से 84 अधिक है?

Solution-: Suppose karte hai ki , n vaa pad iske 13 ve pad se 84 adhik hai. Isliye question me diya hai ki, a = 3, d = 10-3 = 7

Tab n vaa pad = 3+(n-1)×7

Issi prakar se 13 vaa pad =

3+(13-1)×7

= 87

Ab question ke anusaar n vaa pad, 13 vaa pad se 84 adhik hai isliye

⇒3+(n-1)×7 - 84 = 87

⇒ (n-1)×7-81 = 87

⇒ (n-1)×7 = 87+81

⇒ (n-1)×7 = 168

⇒ n-1 = 168/7

⇒ n-1 = 24

⇒ n = 24+1 = 25

Isliye 25 vaa pad iske 13 ve pad se 84 adhik hoga. Ans.

#Q-300. प्रशन. एक दो अंकीय संख्या के अंको का योग 9 है यदि इसमें 27 जोड दिये जाए तो संख्या के अंक उल्ट जाते है तब वह संख्या है?

Solution-: Maana two ankiy sankhya = 10a+b .......(i)

Question ke anusaar, a+b = 9 .....(ii) aur 10a+b+27 = 10b+a

⇒10a-a+b-10b = -27

⇒9a-9b = -27

⇒a-b = -3 ..........(iii)

Eq (i) se, a = 9-b Eq(iii) me rakh kar solve karne par:

⇒ 9-b-b = -3

⇒ 9-2b = -3

⇒ 9+3 = 2b

⇒ 12 = 2b

⇒ b = 12/2 = 6

Isliye a = 9-b = 9-6 = 3

ab hum a = 3 aur b = 6 Eq(i) me rakne par:

10a+b = 10×3+6 = 30+6 = 36 Ans.

#Q-300(i). एक कक्षा मे लड़कियो के 68 व सम्पूर्णकक्षा के 64 औसत अंक है कक्षा में लड़कियो तथा लड़को का अनुपात क्या होगा?

Solution-: Maana ladko ki sankya = X aur ladkiyo ki sankhya = Y

Tab ladko aur ladkiyo ka anupaat = X/Y

Question me diya hai ki, Ladkiyo ka aosat (average) = 68

Isliye

To be continue.......

Sender name -: Bajrang Tanwar
Date-: Jun 27, 2018

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#Q-301. एक दुकानदार त्रुटिपूर्ण तराजू के माध्यम से वस्तुओ को खरीदते समय 10% का घोटाला करता है तथा बेचते समय 10% का घोटाला करता है, उसका लाभ प्रतिशत कितना है?

Solution-: Iss question ko hum shortcut se karte hai.

Shortcut formula:

Profit % = (A+B)+ A×B

100

Formula me , A = Kharidate (buying) time ghotala % aur B = Bechte (selling) time ghotala.

Ab formula me sabhi value rakhkar solve karne par:

Profit % = (10+10)+ 10×10

100

= 20+1 = 21% Ans.

Sender name -: chotu
Date-: Jun 29, 2018

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#Q-302. 4 par ghat X +2y =2 par ghat 4x+10 h to y ki value kya hogi????

Solution-: Hum ye maan lete hai ki aapka question ye hai:

4^x+2y = 2^4x+10 hai to y ki value kya hogi ?

Agar aapka ye question nahi hai to aap jarur bataye. Aap chaahe to question ki image humare Facebook page par send kar sakte hai.

4^x+2y = 2^4x+10

⇒ 2^2(x+2y) = 2^4x+10

⇒ 2^2x+4y = 2^4x+10

⇒ 2x+4y = 4x+10

⇒ 4y = 4x-2x+10

⇒ 4y = 2x+10

⇒ y = 2(x+5)/4

⇒ y = (x+5)/2 Ans.

Sender name -: Khurshida Begum
Date-: Jul 05, 2018

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#Q-303. Mera Q h -2196

Solution-: khurshida ji hume lagta hai ki, aap 2196 ka prime factorization method se square root nikalana jaanana chahti hai.

2| 2196

2| 1098

3| 549

3| 183

61| 61

| 1

Isliye √2196 = √(2×2)×(3×3)×61

= 2×3×√61

= 6√61 Ans.

Sender name -: shiv kumar
Date-: Jul 05, 2018

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#Q-304. hi

Answer-: hi shiv kumar ji boliye hum aapki kya help kar sakte hai ?

Sender name -: Shubham Tiwari
Date-: Jul 11, 2018

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#Q-305. Sir mujhe is question ka samakalan karna hai aap bataenge please qus. xsinx dx

Solution-: ji jarur batayenge. Iss question ko solve karne ke liye hum nichey diye integration formula ka use karenge:

∫uv dx = u∫v dx-∫[(du/dx)×∫v dx]dx

Let u = x

⇒ du/dx = dx/dx = 1 aur

v = sinx

⇒ ∫v dx = ∫sinx dx = -cosx

Ab sabhi value formula me rakhkar solve karte hai.

∫xsinx dx = -xcosx-∫[1×(-cosx)]dx

= -xcosx+∫cosx dx

= -xcosx+sinx+C

= sinx -xcosx+C Ans.

Sender name -: Puja
Date-: Jul 17, 2018

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#Q-306. - ka sign niche kyon nahi hota h

Answer-: Puja ji, aap thoda details me question bataye. Hum samjh nahi paa rahe hai.

Sender name -: Md Abid
Date-: Jul 21, 2018

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#Q-307. O se kisi ank ko multiply karne par 0 hota kaise? Uska detail

Answer-: Kisi bhi ank ka "a" ka dusare ank "b" se multiple karne ka matlab ye huaa ki , "a" ko "b" times add karna.

a×b = a+a+a...b times

Ussi prkar se kisi ank "a" ko "0" se multiply karne ka matlab hai , "a" ko 0 times likhna . Matlab ki "0"

Isliye a×0 = 0 Ans.

Sender name -: Neeraj Kalal
Date-: Jul 19 , 2018

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#Q-308. एक रेलगाडी एक समान चाल से तीन सौ किलोमीटर की दुरी तय करती है यदि तय की गई दुरी की चाल में दस किलोमीटर/घण्टेकी वृद्धि होती है, तो उस रेलगाडी की यात्रा में एक घण्टा का समय कम लेती है तो बताईए कि-(क) रेलगाड़ी की चाल (ख) प्रति बीस सेकेण्ड में यदि दस किलोमीटर/घण्टा की व्रद्धि होने पर एक मिनट में कितनी अधिकतम चाल होगी?

Solution-: Suppose karte hai ki, Train ki speed = X km/h

Isliye time = Distance/speed

= 300/X

Ab question ke anusar, New speed = X+10

Tab time = 300/X+10 aur

⇒ 300 - 300 = 1

X X+10

⇒ 300(X+10) - 300X = 1

X(X+10)

⇒ 300X+3000 - 300X = 1

X(X+10)

⇒ 3000 = 1

X(X+10)

⇒ X(X+10) = 3000

⇒ X²+10X-3000 = 0

⇒ X²+60X-50X-3000 = 0

⇒ X(X+60)-50(X+60) = 0

⇒ (X+60)(X-50) = 0

⇒ X+60 = 0 ⇒ X = -60 (ye speed nahi ho sakta kyuki speed kabhi bhi minus me nahi ho sakta .

Isliye (क) रेलगाड़ी की चाल = X = 50 km/h Ans.

Sender name -: Mohammad Tauheed
Date-: Jul 25 , 2018

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#Q-309. cos^-1√3/2 = ?

Solution-: suppose cos^-1√3/2 = θ ...(1)

⇒ √3/2 = cosθ

⇒ cos 30° = cosθ

⇒ θ = 30°

Eq(1) me "θ" ki value rakhne par:

cos^-1√3/2 = 30° Ans.

Sender name -: Amarnath Dakshine
Date-: Jul 27 , 2018

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#Q-310. prov that v=u+at by samakalan method

Solution-: Hum jaante hai ki, yadi praramhik velocity (initial velocity) = u, antim velocity (final velocity) = v, aur time = t ho to acceleration a = dv/dt (constant)

Tab a = dv/dt

⇒ a dt = dv

dono side samakalan karne par:

limit -: t = 0 se t aur velocity u se v tak .

⇒ ∫a dt = ∫dv

⇒ a∫dt = ∫dv [ kyuki a = constant ]

⇒ a(t-0) = v-u

⇒ at = v-u

⇒ v = u+at proved

Sender name -: ALTAF raja khan
Date-: Jul 30, 2018

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#Q-311. Ap. Kaa 13 pad hai uska yog 143 hai aur 3 pad 5 hai ??

Solution-: Altaf ji sorry, hume aapka question samjh nahi aaya. Please question clear aur detail me bheje.

Sender name -: Neeraj Kalal
Date-: Jul 28 , 2018

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Aapka 2 question hai:

#Q-312. सात मीटर व्यास वाला एक कुआँ खोदा जाता है और खोदने से निकली हुई मिट्टी को समान रूप से फैलाकर बाईस(22) मीटर*पचीस(25) मीटर वाला एक चबूतर बनाया गया है कूएँ की गहराई ग्यात कीजिए।

हल-: माना कूएँ की गहराई = h मीटर और दिया है व्यास (d) = 7 ।

इसलिए त्रिज्या (r) = d/2 = 7/2

कूएँ से निकली गयी मिट्टी का आयतन = कूएँ का आयतन

= πr²h = (22/7)×(7/2)²×h

= 77h/2 ......(i)

चबूतरे का पर फैलाए गए मिट्टी का आयतन = 22×25 = 550 .........(ii)

(i) और (ii) बराबर होंगे, इसलिए

77h/2 = 550

h = 550×2/77 = 14.286

कूएँ की गहराई = 14.286 मीटर (लगभग) Ans.

#Q313. एक डिब्बे में सात लाल कंचे,दस सफेद कंचे और पाँच हरे कंचे है इस डिब्बे में से एक कंचा यदृच्छया निकाला जाता है इसकी प्रायिकता क्या है कि निकाला गया कंचा (क) लाल नही है? (ख) सफेद है? (ग) हरा है ? (घ) चार लाल जबकि दो सफेद (ङ) हरा नहीं है ? (च) लाल है? (छ) सफेद नहीं है ?

हल-: कंचो की कुल
संख्या = 7 लाल + 10 सफेद + 5 हरा = 22
इसलिए 22 कंचो में से एक कंचा निकाल

Sender name -: Alok Patel
Date-: Aug 03, 2018

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#Q-314. Surface area and volume achhe tarike se samjha dijiye

Answer-: Alok ji humne aapki request note kar li hai. Hum jald se jald issko pura karne ki koshish karenge.

Sender name -: Waqas
Date-: Aug 03, 2018

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#Q-315. 4/4(8+2ve)y 2-2u.

Solution-: Waqas ji hume aapka question samjh nahi aaya. Please apna question clear aur details me send kariye.

Sender name -: Ramji rathour
Date-: Aug 06, 2018

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#Q-316. sir mero ko ek sawal samajh me ata pliz tell me

Jaisa ki ham 10 by 10 ka gadhh ek fit gahrai khodenge to o 1 khhanti kahlaygga or yadi ham 3 bay 3 ka gadhh kitni gahrai khode to o ek khhanti kahlaygga?

Solution-: Ramji rathour ji , hume aapke question me kuch mistake laga raha hai. Jaise- 10 bay 10 ka matlab kya hai ? Aur ye "khhanti" kya hai ? Please issko clear kare tab hum aapke question ka answer de paayenge.

Sender name -: Simran sharma
Date-: Aug 12, 2018

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#Q-317. 1 kg apple =50 so 100g apple kitne ke honge

Solution-: 1 kg = 50
⇒ 1000g = 50
⇒ 1g = 50/1000
aur ⇒ 100g = 50×100/1000
= 5
Isliye 100g apple 5 ke honge. Answer

Sender name -: Gopal bajpai
Date-: Aug 13, 2018

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#Q-318. Under root 3 plus one upon 5 - 2 under root 6

Solution-: Gopal ji hume lagta hai ki aapka question ye hai:
√3 +   1
5-2√6
ka maan kya hoga ? Hum issko solve kar rahe hai. Agar aapka ka question ye nahi hai to hume jarur bataye.
√3 +   1
5-2√6
⇒ √3(5-2√6)+1
5-2√6
⇒ 5√3-2√6×√3+1
5-2√6

⇒ 5√3-2√18+1
5-2√6

⇒ 5√3-3√2+1 [2√18 = 3√2]

5-2√6

"Ansh" aur "Har" me 5+2√6 se multiply karne par:

⇒ (5√3-3√2+1)×(5+2√6)

(5-2√6)×(5+2√6)

⇒ 25√3-15√2+5+10√18-6√12+2√6

25-24

⇒25√3+15√2+5+30√2-12√3+2√6

⇒√3(25-12)+√2(15+30)+5+2√6

⇒13√3+45√2+5+√6 Answer.

Sender name -: NARENRA YADAV
Date-: Aug 14, 2018

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#Q-319. Q- 42 ko 7 odd number me decide kaise kare

Solution-: NARENRA YADAV ji hume lagta hai aap jaanana chahte hai ki, 42 ko 7 odd number me divide kaise kare ?

Humare hissab se ye possible nahi hai . 42 ko 7 odd number se divide nahi kar sakte.

Sender name -: Sushil pastor
Date-: Aug 15, 2018

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#Q-320. Progression 17.15.13 ke kitne pdo Ka yogfal 72ke barabar hai

Solution-: Sushil pastor ji hume lagta hai ki, aapka question ye hai:

Progression 17,15,13... ke kitne pado ka yogfal 72 ke barabar hai.

Progression me diya hai a = 17, d = 15-17 = -2 isliye ye ek Arithmetic progression hai.

Suppose karte hai ki, diye gaye progression me n pado ka yogfal 72 ke barabar hai.

Isliye di huyi progression ke n pado ka yogfal =

Sn = n/2[2a+(n-1)d]

72 = n/2[2×17+(n-1)(-2)]

144 = n[34-2n+2]

144 = n[36-2n]

144 = 36n-2n²

2n²-36n+144 = 0

n²-18n+72 = 0

n²-12n-6n+72 = 0

n(n-12)-6(n-12) = 0

(n-6)(n-12) = 0

n = 6 , 12

Isliye diye huye progression 17,15,13... me 6 aur 12 pado ka yogfal 72 ke barabar hoga. Answer.

Sender name -: Mayank

Date-: Aug 16, 2018

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#Q-321. एक सेब को 10480 रु में बेचा जाता है तो 20% लाभ होता है यदि उसे 45% लाभ पर बेचता है तो बिक्रय मूलय निकले

हल-: दिया है : विक्रय मूल्य = 10480 और लाभ = 20%

अतः क्रय मूल्य = विक्रय मूल्य×100

100+लाभ%

= 10480×100

100+20

क्रय मूल्य = 8733.33

अब 45% लाभ पर बेचता है इसलिए,

लाभ = 8733.33×45/100 = 3,930

विक्रय मूल्य = 8733.33+3930 = 12,663.33 Answer.

Sender name -: Purva goswami

Date-: Aug 22, 2018

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#Q-322. Agar sbke liye ek method hoti to aassaan hota

Answer-: Purvs goswami ji, aap kiski baat kar rahi hai ? Please detail me bataye.

Sender name -: Nidhi kumari

Date-: Aug 27, 2018

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#Q-323. Sir mathematics me X ka kya matlab hota hai

Answer-: Nidhi ji, X, ek variable hota hai. Hindi me X ko "char" (चर) kahte hai. Iska use hum question ko solve karne me karte hai.
Jaise-: Ram ki age Mohan ki Age ki 2 guni hai.
To iss question me hum maante hai ki, Mohan ki age = X aur phir X ki value calculate karte hai. I hope ki aapko, aapke question ka answer mil gaya hoga. Koi aur problem ho to jarur puche.

Sender name -: Praveen Kumar

Date-: Sep 02, 2018

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#Q-324. Bodmas kya hai info 1 and 2 page

Answer-: Praveen ji aap ye article read kare-: BODMAS rule kya hai?

Sender name -: Golu Rajput

Date-: Sep 01, 2018

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#Q-325. 3 2/3 + 2 3/4 + 1 1/2 = 7 11/12 how this answer came

Solution-: Hum aapke question ko niche solve kar rahe hai. Koi problem ho to jarur puche.
⇒3 2/3 + 2 3/4 + 1 1/2
= 11/2 + 11/4 + 3/2
= 44+33+18
12
= 95/12

Jab hum 95 ko 12 se divide karenge tab quotient = 7 and remainder = 11
Isliye 95/12 = 7 11/12

Sender name -: Niranjan Kumar

Date-: Sep 07, 2018

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#Q-326. 1-2-1+2=0 Kaise sir?

Solution-: 1-2-1+2 = (1-1)+(2-2)
= 0+0 = 0 Ans.

Sender name -: Rahul

Date-: Sep 09, 2018

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#Q-327. 09+09=

Solution-: 09+09 = 18

Sender name -: SUNIL KUMAR GUPTA

Date-: Sep 14, 2018

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#Q-328. how much does one need to add 2/3 to obtain3/2?

Solution-: Suppose we add "x" in 2/3 we obtaine 3/2, Then
(2/3)+x = 3/2
⇒ x = (3/2)+(2/3)
⇒ x = 9+4
6
⇒ x = 13/6 Answer.

Sender name -: Piyush

Date-: Sep 14, 2018

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#Q-329. Construct ∆ABC such that AB=2.5 cm,BC=6cm and AC=6.5cm.Measure ∆B

Solution-: Solution-: Diya hai -: AB = 2.5 cm, BC = 6 cm aur AC = 6.5 cm
Rachna karni hai -: ∆ABC ki.
Rachna ke charan -:
(1). Sabse pahle ek line AC = 6.5 cm banaya.
(2). Ab Point "A" par compass se ek arc (chaap) 2.5 cm ka layenge.
(3). Ab point "B" par bhi compass se ek dusra arc (chaap) 6 cm ka lagayenge.
(4). Dono chaap jis point par ek - dusre ko cut karenge. Uss point ko "C" se denote karenge.
(5). Point "A", "B" aur "C" ko milane par hum ek ∆ABC milta hai. Yahi triangle humara main triangle hai.
Ab hum iss triangle ke angle /_B ko protractor napenge.
/_B = 90°

To be continue....

Sender name -: Gajendra Singh

Date-: Sep 15, 2018

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#Q-330. 9 se 54 Tak aisi kitni sankhya ha Jo 9 se bhajya ha lekin 3 se nhi

Solution-: Ek bhi sankhya aisi nahi hai. Jo 9 se bhajya ho 3 se nahi.

Sender name -: Tarun pandey

Date-: Sep 15, 2018

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#Q-331. Kisi ki power 0 ho to uski value kya hogi

Answer-: Kisi ke power 0 ho to uski value 1 hoti hai.

Sender name -: SURENDRA KUMAR

Date-: Sep 16, 2018

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#Q-332. Pythagoras trick

Solution-: Surendra ji, Pythagoras ke trick to abhi humare paas nahi hai. Agar future me hume koi idea mila to hum jarur batayenge. Haa lekin Pythagoras theorem aur iss se related question ko humne solve karna sikhaya hai. Aap yaha se padh sakte hai-:Pythagoras theorem with related questions

Sender name -: Ankesh mall

Date-: Sep 17, 2018

Kaise send kiya -: Contact form

#Q-333. 84ko 7:5

Solution-: Ankesh ji, please complete question bhejiye.

Sender name -: Ashish

Date-: Sep 18, 2018

Kaise send kiya -: Comment

#Q-334. SIR MUJHE SAMAJHNE M PROBLEM AA RHI HAI MERA MATH WEEK HAI PLZ HELP KRIYE..SIR YEH ISMEY ISE(2+1/7))]} SOLVE KRNE PR YEH 15/7)]} KAISE AAYA ?

Solution-: ASHISH ji aapki math week hai to kya huaa ? Hum aapki math strong banayenge.
2+1/7 me 2 ke "har" me kuch nahi hai tab hum 2 ke niche 1 laga sakte hai.
2 + 1 = 14+1 = 15 Ans.
1 7 7 7

Sender name -: Jitendra Rana

Date-: Sep 19, 2018

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#Q-335. 60 rupaye ko 9logo batna h visham Sankhya me

Solution-: To be continue....

Sender name -: Rishabh shankhwar

Date-: Sep 19, 2018

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#Q-336. Very very nice shortcut tricks bhaiya 😊😊
But Bhaiya aapne 4 to 6 digit ka bataya h And sabhi cube root 100 se kam ke h 100 se upar ke cube root nukalne ki tricks h kya bhaiya?

Solution-: Rishabh ji, aapko cube root tricks aacha laga isske liye aapko very-very thanks !!
Second hum jald hi 100 se upar number ke cube tricks nikalana batayenge. Aap humare saath bane rahiye.

Sender name -: Arbaaz

Date-: Sep 24, 2018

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#Q-337. dy/dx kia hai d/dx kya hai

Solution-: Arbaaz ji, issko avkalan (differentiation) kahte hai. Isska matalab ye huaa ki, " kisi char (variable) y ka kisi dusre char x ke sambandh me bahot kam samay me hone waale change ki dar (rate) ko differentiation (avakalan) kahte hai."
d/dx kewal ek notation hai. Jo differentiation ko prakat karta hai.

Sender name -: Sarita

Date-: Sep 25, 2018

Kaise send kiya -: Comment

#Q-338. (3/6+1/2)/5/4+(2/4*7/8)/9/4

Solution-:  3/6+1/2 + 2/4*7/8
5/4 9/4
   3+3       2×7
⇒    6   + 4×8
5/4 9/4
   6      14
⇒    6   + 32
5/4 9/4
      7
⇒    1   + 16
5/4 9/4
⇒   4 + 7×4
5 16×9
⇒   4 + 7
5 4×9
⇒   4 + 7
5 36
⇒   144+35
180
⇒   179   Answer.
180

Sender name -: Shoaib Akhtar

Date-: Sep 25, 2018

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#Q-339. (X-Y)^6-8x^3

Solution-: Binomial expansion formula use karne par-:
Binomial expansion formula: (x+y)ⁿ = ⁿC₀xⁿy⁰+ⁿC₁xⁿ^-¹y¹+ⁿC₂xⁿ^-²y²+.....+ⁿC_nx⁰y⁶
(X-Y)⁶ = {X+(-Y)}⁶
= ⁶C₀X⁶(-Y)⁰+⁶C₁X^6-1(-Y)¹+⁶C₂X^6-2(-Y)²+⁶C₃X^6-3(-Y)³+⁶C₄X^6-4(-Y)⁴+⁶C₅X^6-5(-Y)⁵+⁶C₆X^6-6(-Y)⁶
= ⁶C₀X⁶(-Y)⁰+⁶C₁X⁵(-Y)¹+⁶C₂X⁴(-Y)²+⁶C₃X³(-Y)³+⁶C₄X²(-Y)⁴+⁶C₅X¹(-Y)⁵+⁶C₆X⁰(-Y)⁶
= ⁶C₀X⁶(1)+⁶C₁X⁵(-Y)+⁶C₂X⁴Y²-⁶C₃X³Y³+⁶C₄X²Y⁴-⁶C₅XY⁵+⁶C₆Y⁶

Ab hum jaante hai ki, ⁶C₀ = 1, ⁶C₁ = 6, ⁶C₂ = 15, ⁶C₃ = 20, ⁶C₄= 15, ⁶C₅ = 6, aur ⁶C₆= 1
Sabhi value rakhne par:
(X-Y)⁶ = X⁶-6X⁵Y+15X⁴Y²-20X³Y³+15X²Y⁴-6XY⁵+Y⁶
(X-Y)⁶-8X³ = X⁶-6X⁵Y+15X⁴Y²-20X³Y³+15X²Y⁴-6XY⁵+Y⁶-8X³ Answer.

Sender name -: Hardip talukdar

Date-: Sep 29, 2018

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#Q-340. 17se kiya -karne se 13 ayega Lekin -4nehi hoga

Solution-:Hardip ji, 17 me se 4 minus karne par 13 aayega.

Sender name -: SUDHANSHU PAL

Date-: Oct 03, 2018

Kaise send kiya -: comment

#Q-341. Sir वह छोटी से छोटी number find करे । जिसे add पर 4000 एक perfect squre बन जाए

Solution-: Sudhanshu ji, 4000 ka long division method se square root nikalana hai. Jaisa humne niche kiya hai.

Aap dekh sakte hai ki, remainder -96 hai. Matlab ki 4000 me 96 add kar denge to 4000 perfect square ban jaayega.

Sender name -: DJ KAMLESH KAMESHWAR

Date-: Oct 04, 2018

Kaise send kiya -: comment

#Q-342. 4 1/2 + 1/8
____________
3/8 - 1/4 solved this Math

Solution-: 4 1/2 + 1/8 = 9/2 + 1/8
= (36+1)/8
= 37/8
aur 3/8 - 1/4 = (3-2)/8 = 1/8

4 1/2 + 1/8 = 37/8 = 37 Answer.
3/8 - 1/4 1/8

Sender name -: Vishal kumar

Date-: Oct 04, 2018

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#Q-343. Log 8 ko solve kase kre mind se

Solution-: Vishal ji, aapka question complete nahi hai. Aapne base to bataya hi nahi.

Sender name -: Abhishek yadav

Date-: Oct 08, 2018

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#Q-344. Mujhe math nahi aatii hai sirji Please help me

Solution-: Abhishek ji, hum aapki jarur help karenge. Aap bataye ki, aapko math me kya problem ho rahi hai ?

Sender name -: Rahan Ansari

Date-: Oct 12, 2018

Kaise send kiya -: contact form

#Q-345. Mujhe ek question puchna hai

Solution-: Rahan ji, boliye aapko kya puchana hai?

Sender name -: vinay kumar

Date-: Oct 12, 2018

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#Q-346. 120 ka 20% kiya hai aur 20% add karne par wo phir phele ke = ho jaye.

Solution-: vinay ji, aapka question samjh me nahi aaya. Hume jaha tak samjh aaya . Hum waha tak bata rahe hai. jab hum 120 ka 20% nikalenge tab
120×20% = 120×20/100
= 24
Isske baad nahi samjh aaya aap isske baad bataye.

Sender name -: Rahul

Date-: Oct 15, 2018

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#Q-347. Koi cheej 100 rupees kilo hain to 20rupees ka 250gm aayega hanceproof kar dijiye

Solution-: Rahul ji, 250gm ,₹25 ka hoga ₹20 ka nahi. Humne niche proof kiya hai.
⇒1kg = ₹100
⇒1000gm = ₹100
⇒1 gm = ₹ 100/1000
⇒250gm = ₹ 250×100/1000
= ₹25

Sender name -: Pawan Kumar Patel

Date-: Oct 16, 2018

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#Q-348. प्रश्न-तीन अंको की छोटी से छोटी संख्या बताओ जो 4,8,16 से पूरी पूरी बँट जाये? हल कैसे करेंगे ।

Solution-: Sabse pahle 4,8 aur 16 ka L.C.M. nikalenge.
2|4, 8, 16
2|2, 4, 8
2|1, 2, 4
2|1, 1, 2
|1, 1, 1

4, 8 aur 16 ka L.C.M = 2×2×2×2 = 16
Aap dekh sakte hai ki , L.C.M = 16 hai isska matlab hume 3 digit ka wo number maalum karna hai jo 16 ka multiple (gunaj) ho.
So , 16×1 = 16
16×2 = 32
16×3 = 48

16×4 = 64

16×5 = 80

16×6 = 96

16×7 = 112

Aap dekh sakte hai ki, 16×7 = 112 , 3 digit number hai. Jo 4, 8 aur 16 se puri puri tarh se divide ho jaayega.

So Answer = 112

Sender name -: Vaibhav pratap
Date-: Oct 20, 2018

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#Q-349. Tribhuj ke teeno kodh ka yog 180 hota hai sidh kro(prema) please answer me

Solution-: Vaibhav ji, humne issko sidh kiya hai. Aap ye padhe-: Prove that sum of the angles of triangle is 180 degrees

Sender name -: Raj Shankar kr
Date-: Oct 26, 2018

Kaise send kiya -: Facebook page par massage

#Q-350. 600 रुपए को A, B तथा C इस प्रकार विभक्त किया गया है कि A के भाग के 2/5 से 40 रुपए अधिक, B के भाग के 2/7 से 20 रुपए अधिक तथा C के भाग के 9/17 से 10 रुपए अधिक सभी बराबर हैं। A का भाग है -
(1) 180 (2) 160 (3) 150 (4) 140

Solution-: Suppose karte hai ki, A ka bhag = x , B ka bhag = y.
Tab, C ka bhag = 600-(x+y)
Ab question ke anusar,
2x/5 +40 = 2y/7 +20 = 9{600-(x+y)}/17 +10 .......(*)
Ab Eq(*) se,
⇒2x/5 +40 = 2y/7 +20
⇒2y/7 - 2x/5 = 40-20
⇒2y/7 - 2x/5 = 20
⇒y/7 - x/5 = 10
⇒5y-7x = 350 ......(i)

Ek baar phir Eq(*) se,
⇒2x/5 +40 = 9{600-(x+y)}/17 +10
⇒2x/5 +40 = (5400-9x-9y)/17 + 10
⇒2x/5 +40 = 5400/17 - 9x/17 -9y/17 +10
⇒2x/5 + 9x/17 + 9y/17 = 5400/17 - 40+10
⇒(34x+45x+45y)/85 = 5400/17 -30
⇒(79x+45y)/85 = (5400-510)/17
⇒(79x+45y)/85 = 4890/17
⇒79x+45y = 24450 ......(ii)

Eq(i) me 9 se multiply karne par-:
45y-63x = 3150 .....(iii)

Ab (iii) ko (ii) se minus karne par-:
79x+45y = 24450
-63x+45y = 3150
+ - -
142x = 21300

Means , 142x = 21300
x = 21300/142
= 150
Isliye A ka bhag = 150 rupaye Answer.
Options (3) 150✔️

Sender name -: Rajpal Singh
Date-: Oct 28, 2018

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#Q-351. 2 ki power 81 me kitne ank hoge

Solution-: Sorry, Rajpal ji, iss type ke question ke liye humare paas koi idea nahi.

Sender name -: Hemant netam
Date-: Nov 01, 2018

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#Q-352. हमें ४०० ग्राम में से १/२(आधा) ग्राम घटना है , कैसे घटाएं । कृपया बताएं।

Solution-: Hemant ji , 400 gm me se 1/2(aadha) gm ghatana hai. Isska matalab ye huaa ki, 400gm me se 0.5 gm ghatana hai. Jo iss prakar se hum ghatayenge-:
  400.0
   - 0.5
   399.5     Answer.

Sender name -: Alkama
Date-: Nov 13, 2018

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#Q-353. 10% KO agar rupees mein change kare to kitna hoga

Solution-: Alkama ji, aapke question me hume kuch mistake ya wrong lag raha hai. Hum aapke question ko solve nahi kar paa rahe hai.